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Explanation of Derivation of Velocity-Time Gravity Equations - Succeed in Understanding Physics. Also refer to physical science, falling objects, Calculus, acceleration, velocity, integral, derivative, integrate, distance, time, relationships, Ron Kurtus, School for Champions. Copyright © Restrictions

Derivation of Velocity-Time Gravity Equations

by Ron Kurtus (revised 10 August 2010)

The basis for the derivations of the velocity-time gravity equations starts with the assumption that the acceleration due to gravity is a constant value.

Since acceleration is also the change in velocity for an increment of time, you use Calculus to integrate that change to get the velocity for a given elapsed time. From the velocity equation, you can then determine the equation for the time it takes for the object to reach a given velocity from the starting point.

The derived equations are affected by the initial velocity of the object. This is important in later applications of the equations.

Questions you may have include:

This lesson will answer those questions. There is a mini-quiz near the end of the lesson.

Useful tools: Metric-English Conversion | Scientific Calculator.

Basis for velocity-time derivations

The derivations start with the assumption that the acceleration due to gravity g is a constant for distances relatively close to Earth.

Acceleration is also the incremental change in velocity with respect to time:

a = dv/dt

where

Since g is the acceleration due to gravity:

a = g

and

dv/dt = g

Multiply both sides of the equation by dt to get:

dv = g*dt

By using Calculus to integrate this equation, you can get the equations for velocity and time.

Velocity-time relationship

Velocity-time relationship

Derivation of velocity for a given time

Integrate dv = g*dt on both sides of the equal sign.

First, integrate dv over the interval from vi to v:

∫dv = v − vi

where

Then, integrate g*dt over the time interval from 0 to t:

∫g*dt = gt − 0

The result of the integrations is:

v − vi = gt

The general gravity equation for velocity with respect to time is:

v = gt + vi

However, the value of the initial velocity affects the equation.

vi = 0

When the object is simply dropped, the initial velocity is zero (vi = 0) and the equation becomes:

v = gt

vi > 0

When the object is thrown downward, the initial velocity is greater than zero
(vi > 0) and the velocity is also positive.

vi < 0

When the object is projected upward, the initial velocity is less than zero (vi < 0) and v is negative on the way up, zero at the maximum height and positive on the way down.

Derivation of time for a given velocity

The time it takes to reach a given velocity is obtained by rearranging the equation v = gt + vi and solving for t:

v = gt + vi

v − vi = gt

t = (v − vi)/g

Again, the value of the initial velocity affects the equation.

vi = 0

When the object is dropped, the initial velocity is zero (vi = 0) and the equation becomes:

t = v/g

vi > 0

Since t cannot be negative, v must be greater than or equal to vi when the object is thrown downward.

vi < 0

When the object is projected upward, both v and vi are negative on the way up. At the maximum height, v = 0 and the equation becomes:

tm = − vi/g

where

Then, on the way down, v is a postive number.

Summary

Starting with the fact that the acceleration due to gravity g is considered a constant and knowing that acceleration is the change in velocity for a change in time, you can derive the gravity equations for the velocity with respect to time. You can then determine the equation for the time to reach a given velocity.

The derived equations are:

v = gt + vi

t = (v − vi)/g

tm = − vi/g (at maximum height when projected upward)

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Resources

The following resources provide information on this subject:

Websites

Acceleration due to Gravity Calculations - from Western Washington University

Gravity and Gravitation Resources

Books

Top-rated books on Simple Gravity Science

Top-rated books on Advanced Gravity Physics


Mini-quiz to check your understanding

1. What does dv/dt stand for?

It is d times v divided by d times t

It has no real meaning

It is a small change in velocity divided by an increment in time

2. Why is g*dt integrated over the time interval 0 to t?

You are starting from zero time to some arbitrary time

The initial velocity is 0

Because g can vary between 0 and t

3. How is the equation for time with respect to a given velocity determined?

Integrate the velocity equation over time

Take the velocity for a given time equation and solve for t

There is no equation for time with respect to a given velocity

If you got all three correct, you are on your way to becoming a Champion in Physics. If you had problems, you had better look over the material again.


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