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Explanation of Gravity Distance Equations for Objects Projected Downward - Succeed in Understanding Physics. Also refer to physical science, acceleration, velocity, time, calculation, square-root, Ron Kurtus, School for Champions. Copyright © Restrictions

Gravity Distance Equations for Objects Projected Downward

by Ron Kurtus (28 August 2009)

If you know the initial velocity that an object is thrown or projected downward, you can calculate the distance traveled from the starting point when the object reaches a given velocity or when it reaches a given elapsed time. Some examples illustrate these equations.

The equations were determined from the Derivation of Gravity Equations and are summarized in Overview of Gravity Equations for Objects Projected Downward.

Note: You normally do not need to memorize these equations, but you should know where to find them in order to solve equations.

Questions you may have include:

This lesson will answer those questions. There is a mini-quiz near the end of the lesson.

Useful tools: Metric-English Conversion | Scientific Calculator.

Distance for a given velocity

If you throw an object downward at some initial velocity, the equation for the distance traveled to reach a given velocity is:

x = (v2 − vi2)/2g

where

Distance of an object thrown downward as a function of initial velocity and velocity or time

Distance of an object thrown downward as a function of
initial velocity and velocity or time

Distance for a given time

If you throw an object downward, the equation for the distance traveled within a given time is:

x = gt2/2 + vit

where t is the time the object has fallen in seconds (s).

Examples

The following examples illustrate applications of the equations.

For a given velocity

If you throw an object downward at 10 m/s, find the minimum height you must throw it from so that it reaches 50 m/s.

Solution

You are given that vi = +10 m/s and v = 50 m/s. Since vi and v are in m/s,
g = 9.8 m/s2. The equation to use is:

x = (v2 − vi2)/2g

Substitute values in the equation:

x = [(50 m/s)2 − (10 m/s)2]/2*(9.8 m/s2)

x = [(2500 m2/s2) − (100 m2/s2)]/(19.6 m/s2)

x = (2400 m2/s2)/(19.6 m/s2)

x = 122.4 m

For a given time

If you throw an object downward at 30 ft/s and it travels for 4 seconds, find the distance traveled.

Solution

You are given that vi = 30 ft/s and t = 4 s. Since vi is in ft/s, g = 32 ft/s2. The equation to use is:

x = gt2/2 + vit

Substitute values in the equation:

x = [(32 ft/s2)*(4 s)2]/2 + (30 ft/s)*(4 s)

x = (32 ft/s2)*(16 s2)/2 + 120 ft

x = (512 ft)/2 + 120 ft

x = 256 ft + 120 ft

x = 376 ft

Summary

You can calculate the distance traveled from the starting point when an object that is projected downward reaches a given velocity or when it reaches a given elapsed time from the equations:

x = (v2 − vi2)/2g

x = gt2/2 + vit

Answers to Readers' Questions

See the Side Menu for more Gravitation and Gravity topics


Check your numbers


Resources

The following resources provide information on this subject:

Websites

Acceleration due to Gravity Calculations - from Western Washington University

Gravitation and Gravity Resources

Books

Top-rated books on Simple Gravity Science

Top-rated books on Advanced Gravity Physics


Mini-quiz to check your understanding

1. If you throw an object downward at 8 ft/s, how far does it travel when it reaches 20 ft/s?

20 feet

5.25 feet

2 feet

2. If you throw an object downward at 10 m/s, how far does it travel in 2 s?

39.6 meters

10 meters

1 meter

3. If you throw an object downward at 10 ft/s, how far does it travel in 2 s?

8.4 feet

84 feet

840 feet

If you got all three correct, you are on your way to becoming a Champion in Physics. If you had problems, you had better look over the material again.


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