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# Energy from Gravity for Objects Projected Upward

by Ron Kurtus

When an * object is projected upward* from a given height, it travels until it reaches a maximum displacement, at which time its velocity is zero. The object then falls to the ground from that displacement.

You can calculate the **PE**, **KE** and total energy (**TE**) for an object that is projected upward with some simple equations. You can then verify that the final velocity is the same as obtained from the gravity derivations.

Questions you may have include:

- What is the energy and final velocity for a dropped object?
- What is the energy and final velocity for an object thrown downward?
- What is the energy and final velocity for an object projected upward?

This lesson will answer those questions. Useful tool: Units Conversion

## Potential energy when projected upward

The initial potential energy of an object projected upward is:

PE_{i}= mgh

As the object is moving upwards, the **PE** increases according to its displacement. The maximum displacement is:

y_{m}= −v_{i}^{2}/2g

where **y _{m}** is the maximum displacement from the starting point.

(

See Displacement Equations for Objects Projected Upward for more information.)

Note: The value ofyis a negative number, because the motion is in the opposite direction of gravity._{m}

However, the object is projected upward from a given height. Thus, the maximum height above the ground (**h _{m}**) that it reaches is:

h_{m}= h − y_{m}_{}

The equation for the **PE** at the maximum height is then:

PE_{m}= mgh_{m}

or

PE_{m}= mgh− mgy_{m}

Substituting for **y _{m}**:

PE_{m}= mgh + mv_{i}^{2}/2

Considerations concerning **PE** can be made from the initial height.

## Kinetic energy when projected upward

The initial **KE** is:

KE_{i}= mv_{i}^{2}/2

At the maximum displacement, **v =** 0 and thus:

KE0_{m}=

When the object falls and finally reaches the ground:

KE_{f}= mv_{f}^{2}/2

## Total energy and final velocity

To determine the final velocity, consider the total energy at the maximum displacement and compare it with the total energy at the ground:

PE_{m}+ KE_{m}= PE_{f}+ KE_{f}

(mgh + mv0_{i}^{2}/2) +=0+ mv_{f}^{2}/2

Divide by **m**, multiply by 2 and rearrange terms to get the final velocity:

v_{f}^{2}= 2gh + v_{i}^{2}

v_{f}= √(2gh +v)_{i}^{2}

This compares with the equation in Velocity Equations for Objects Projected Upward:

v = √(2gy +v)_{i}^{2}

where **y** is the displacement below the starting point.

## Summary

Potential energy with respect to gravity is **PE = mgh**. When the object is dropped, thrown downward or projected upward, its kinetic energy becomes **KE = mv ^{2}/2**, along with a factor of the initial velocity.

The sum of the **PE** and **KE** is the total energy, which is a constant. Equating the initial total energy with the final total energy, you can determine the final velocity of the object.

Gain confidence through small successes

## Resources and references

### Websites

**Gravity and Potential Energy** - University of Alaska

### Books

(Notice: The *School for Champions* may earn commissions from book purchases)

**Top-rated books on Simple Gravity Science**

**Top-rated books on Advanced Gravity Physics**

## Questions and comments

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## Where are you now?

## Energy from Gravity for Objects Projected Upward